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Reviews: ARE THERE ANY HOMEOPATHIC REMEDIES FOR CHALAZIONS?

ARE THERE ANY HOMEOPATHIC REMEDIES FOR CHALAZIONS?

Question by teamirish82:
Are there any homeopathic remedies for chalazions?

This is my second chalazion in two years. I had the first surgically removed with disasterous final results. I want to go the normal route. Other than hot compress, cleaning regularly with child shampoo, and no makeup are there any supplements or homeopathic remedies that have been identified to aid?
The mass is somewhat hardened. I have had good luck with the hot compresses, cleansing, and tea tree oil twice a day.


——————————————

Answer by Nurses are Angels
http://abchomeopathy.com/c.php/34

try that dear…

Answer by jd88
Is it puss filled or is it a hard mass?
From the details you have provided so far, I would state try Silicea 30C twice a day. Silicea has the capacity to draw puss out of the eye and if it is right for you, you will see your chalazion decrease in size in a month or two (depending on size it will take longer). Right after that, take Hepar Sulph 30C which heals the puss wound. Then take Staphysagria 30C each day to avoid additional chalazions as individuals who create chalazions are prone to an additional.

Answer by SkepDoc two.
No there are not. Homeopathy is a placebo remedy.

You are quite proper in the use of frequent hot compresses and lid hygeine. Opthalmologists do not like to do the surgical remedy either, as there are usually some cosmetic problems with scarring of the eyelid.

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Anang's Blog

Anang's Blog


TRIK UN MATEMATIKA SMA 2012

Posted: 12 Nov 2011 05:06 AM PST


Bismillah, berikut ini adalah prediksi SKL UN Matematika SMA kelas XII IPA 2012 berdasarkan analisis bedah SKL UN 2011. Saya sertakan juga tips dan trik logika praktis dalam menghadapi soal Ujian Nasional yang diperkirakan bakal keluar.

Semoga bermanfaat...


TIPS DAN TRIK UN MATEMATIKA SMA 2012

PREDIKSI SKL UN MATEMATIKA SMA 2012

Berdasarkan Analisis dan Bedah SKL UN 2011

(Oleh Anangku http://www.facebook.com/anangku)


SKL 1. LOGIKA MATEMATIKA
  1. Penarikan kesimpulan :
    Logika sederhana mengingat kontraposisi, jika motor bisa lewat maka mobil juga bisa lewat. Lha jika mobil tidak bisa lewat, maka motor tidak bisa lewat.
    Logika sederhana mengingat arti jika maka, jika bukan rabu maka kamis, jika bukan kamis maka rabu, maka artinya rabu atau kamis. (Jika pada jawaban tidak menemukan implikasi maka bisa diganti dengan disjungsi)
    Ingat cara penarikan kesimpulan silogisme. Coret yang sama.


SKL 2. ALJABAR
  1. Aturan Pangkat
    (Trik: tanda x berubah menjadi +, dan tanda / berubah menjadi –, dikurung bagi adil, dipangkat jadi dikalikan)
  2. Aturan Akar:
    Merasionalisasi bentuk akar. Teknik merasionalisasi adalah mengalikan bentuk akar dengan 1. Tetapi 1 itu diganti pembagian dua bentuk akar tsb atau pembagian dua bentuk sekawan akar.
    Menyederhanakan bentuk akar.
  3. Persamaan Logaritma:
    Jika bentuk soalnya adalah diketahui
    2log 3 = a, 3log 5 = b, ditanya bentuk logaritma yang lain, maka tambahkan satu yang diketahui yakni cari bilangan yang sama dan tetapkan 3log 3=1.
    Jika ketemu 3 tulis a, jika ketemu 5 tulis b, jika ketemu 3 tulis 1.
    (Trik: Ingat konsep alog b = log b / log a)
    Jika persamaan logaritma mirip Persamaan Kuadrat (PK), maka kerjakan dengan memfaktorkan PK tersebut.
  4. Diskriminan fungsi Persamaan Kuadrat (PK):
    Jika fungsi PK memotong sumbu x maka D>0, menyinggung D=0, tidak menyinggung atau tidak memotong D<0
  5. Rumus Jumlah Kali Akar PK:
    Jika ax
    2 + bx + c = 0, maka: x1 + x2 = - b/a, x1 + x2 = - c/a.
    x
    1 + x2 = 0, maka nilai b = 0,
    x
    1 . x2 = 1 (akar saling berkebalikan), maka nilai c = a,
    x
    1 - x2 = n, maka D = (na)2 ,
    x
    1 = x2 , maka D = 0. Artinya b2 = 4 ac
    x
    1 = nx2 maka, shg n.b2 = (n+1)2. ac (Trik: Angka 1 = n, angka 4 = (n+1)2)
  6. Menyusun PK Baru:
    Gunakan sifat jumlah hasil kali akar.
    (Trik: subtitusi invers dari akar baru)
  7. Persamaan Garis Singgung (PGS) Lingkaran:
    Jika diketahui m = gradien maka PGS lingkaran adalah y = mx ± r √(1+m
    2).
    (Trik: PGS lingkaran adalah turunan dari fungsi lingkaran)
  8. Fungsi Komposisi:
    Ingat (fog)(x)=f(g(x)), artinya substitusikan g(x) ke f(x).
    (Trik: gunakan konsep perkalian kanan kiri Matriks)
  9. Fungsi Invers:
    Jika f(x) = (ax-b) / (cx-d) maka f
    -1(x) = (dx-b) / (cx-b), tukar negative antara a dan d.
    (Trik: balik operasi lalu balik urutan)
  10. Teorema Sisa:
    Ingat, sisa adalah nilai fungsi. Sisa pembagian oleh (x-a) adalah f(a).
    (Trik: pembagi samadengankan nol)
  11. Teorema Faktor:
    Gunakan cara horner biasa atau bertingkat.
  12. Sistem Persamaan Linear:
    Gunakan metode eliminasi substitusi.
    (Trik: Gunakan metode determinan matriks)
  13. Program Linear:
    Menentukan nilai optimum.
    (Trik: Gunakan sifat gradien atau garis selidik)
  14. Matriks:
    Ingat sifat determinan matriks. |A
    -1| = |A|-1 dan |AT|=|A|
  15. Sudut antara dua vektor:
    cos θ = (a.b) / (|a||b|)
  16. Panjang proyeksi atau vektor proyeksi:
    Proyeksi a ke b,|c| = |a| cos θ, c = |c| b
  17. Komposisi dua transformasi:
    Ingat sifat fungsi komposisi.
    (Trik: matriks hasil transformasi adalah berisi bayangan transformasi titik A(1,0) dan B(0,1). Kolom 1 diisi hasil transformasi A, kolom 2 hasil transformasi B)
  18. Invers Fungsi Eksponen dan Logaritma:
    Ingat sifat eksponen dan logaritma yang saling invers.
    alog b = c <=> ac = b
    (Trik: cara membaca searah jarum jam dari a)
  19. Suku ke-n Deret Aritmatika:
    Gunakan metode eliminasi substitusi.
    (Trik: jika Un menyatakan suku ke-n, beda adalah selisih Un dibagi selisih n)
  20. Deret Aritmatika atau Geometri:
    Gunakan rumus jumlahan deret.


SKL 3. GEOMETRI
  1. Jarak Dua Objek:
    Ingat jarak terpendek selalu tegak lurus dengan garis.
    Gunakan aturan Pythagoras, dan aturan trigonometri.
  2. Sudut Dua Objek:
    Ingat sifat aturan sinus atau cosinus.
    Gunakan aturan Pythagoras, dan aturan trigonometri.


SKL 4. TRIGONOMETRI
  1. Aturan Sinus Cosinus Pada Segi Banyak:
    Ingat aturan sinus. Perbandingan sudut dan sisi berhadapan adalah konstan.
    Ingat aturan cosinus. Mirip aturan Pythagoras, tapi ada tambahan +2ab cos θ
    .
  2. Volume Bangun Ruang menggunakan aturan Sinus Cosinus:
    Aplikasi aturan sinus cosinus untuk menentukan volume bangun ruang.
    Ingat luas bangun ruang berbentuk prisma adalah luas alas kali tinggi, bangun ruang berbentuk kerucut sepertiga luas bangun ruang prisma.
  3. HP Persamaan Trigonometri:
    Gunakan sifat trigonometri sudut kelipatan periode fungsi trigonometri, bawa ke bentuk kuadran, lalu bawa ke bentuk kuadran I.
    (Trik: menentukan nilai sudut trigonometri, ingat pola nilai trigonometri kuadran I s/d IV, atau bentuk grafik fungsi trigonometri)
  4. Menghitung Rumus Jumlah Selisih Trigonometri:
    Gunakan aturan rumus jumlah selisih trigonometri.
    (Trik: kalau iSIN maka yang ngeKOS DISEMBUNYIKAN, kalau pengen ngeKOS ayo ngeKOS BARENG-BARENG yang iSIN GAK USAH IKUT)
  5. Menganalisis Rumus Jumlah Selisih Trigonometri:
    Gunakan aturan rumus jumlah selisih trigonometri untuk menentukan nilai trigonometri yang lain.


SKL 5. KALKULUS
  1. Limit Aljabar:
    Nilai limit yang diperbolehkan adalah selain bentuk tak tentu berikut: 0/0, ∞/∞, ∞±∞.
    (Trik: aturan L'hopital, gunakan turunan untuk menyelesaikan limit, dan sifat turunan modifikasi untuk limit bentuk akar.)
  2. Limit Trigonometri:
    Ingat sifat identitas trigonometri, khususnya cos 2x.
    (Trik: SINTA CORET, hilangkan notasi sin tan. Sementara untuk COS, CORET semua jika nilainya 1 dan UBAH bentuk COS yang nilainya 0 atau bentuk (1 – cosθ ) atau (cosθ – 1))
  3. Aplikasi Fungsi Turunan:
    Nilai optimum didapatkan dari turunan fungsi samadengan nol. Dinotasikan, f(x) optimum pada x yang memenuhi f'(x) = 0. Penyelesaiannya mungkin menggunakan aturan dan sifat PK.
  4. Integral Tak Tentu Aljabar:
    Teknik pengerjaan integral:
    1. Langsung (bila bukan perkalian atau pembagian, sesuai dengan aturan integral yakni pangkat terlihat jelas),
    2. Harus diubah bila masih memungkinkan untuk dikerjakan (biasanya bentuk fungsi berpangkat, bentuk pembagian yang bisa disederhanakan, bentuk akar yang pangkatnya tidak Nampak, dll)
    3. Substitusi (dimana turunan fungsi yang disubstitusikan adalah perkalian skalar dari fungsi diluar fungsi berpangkat)
    4. Parsial (jika langkah 1, 2, atau 3 bentuk integral masih tidak memungkinkan untuk diselesaikan)
    (Trik: integral parsial juga bisa diselesaikan menggunakan metode tabulasi)
  5. Integral Tak Tentu Trigonometri:
    Teknik pengerjaan integral trigonometri:
    1. Langsung bila terdapat bentuk diantara 6 turunan fungsi trigonometri (turunan sin, cos, tan, sec, cosec, dan cotan. Keenam turunan fungsi trigonometri ini wajib hafal).
    2. Diubah, bila masih memungkinkan munculnya bentuk 6 turunan fungsi trigonometri dengan menggunakan aturan identitas trigonometri. Atau jika masih terdapat bentuk perkalian, gunakan sifat rumus perkalian dua trigonometri menjadi penjumlahan atau pengurangan trigonometri.
    3. Substitusi, bila terdapat sin atau cos berpangkat satu ditemani cos atau sin berpangkat lebih dari satu. Atau bila terdapat gabungan fungsi aljabar dan trigonometri dimana turunan nilai sudut trigonometri adalah perkalian skalar dari fungsi aljabar tersebut.
    4. Parsial, bila langkah 1, 2, atau 3 masih tidak memungkinkan bentuk integral untuk diselesaikan.
    (Trik: integral parsial juga bisa diselesaikan menggunakan metode tabulasi)
  6. Integral Tertentu Aljabar:
    Setelah menyelesaikan hasil integral, dilanjutkan dengan menghitung hasil substitusi batas atas ke lantas dikurangi hasil substitusi oleh batas bawah. (Trik: untuk mempercepat proses perhitungan lakukan perhitungan hasil substitusi x sekaligus dikurangi hasil substitusi batas bawah)
  7. Integral Tertentu Trigonometri:
    Setelah menyelesaikan hasil integral, dilanjutkan dengan menghitung hasil substitusi batas atas ke lantas dikurangi hasil substitusi oleh batas bawah.
    (Trik: untuk mempercepat proses perhitungan lakukan perhitungan hasil substitusi x sekaligus dikurangi hasil substitusi batas bawah)
  8. Integral untuk Luas Daerah:
    Luas daerah yang dibatasi fungsi dan garis batas bawah a dan batas atas b adalah INTEGRAL TERTENTU dari a ke b dari fungsi. Sumbu garis batas menentukan operator integral yang digunakan. Bila fungsi dan operator belum sesuai maka gunakan sifat fungsi invers.
    Ingat bila terdapat dua grafik maka tentukan dulu grafik mana yang memiliki nilai lebih besar.
    (Trik: gunakan nilai determinan untuk menyelesaikan luas dengan cepat jika hanya diketahui satu atau dua fungsi tanpa garis batas, atau sifat luas besar luas kecil bila grafiknya diketahui)
  9. Integral untuk Volume Benda Putar:
    Volume benda putar yang dibatasi garis batas bawah a dan garis batas atas b adalah π dikalikan integral tertentu dari a ke b dari kuadrat fungsi. Sumbu garis batas menentukan operator integral yang digunakan. Bila fungsi dan operator belum sesuai maka gunakan sifat fungsi invers.
    Ingat bila terdapat dua grafik maka tentukan dulu grafik mana yang memiliki nilai lebih besar.
    (Trik: gunakan nilai determinan untuk menyelesaikan volume dengan cepat bila hanya diketahui satu fungsi dan hanya dibatasi garis sumbu)


SKL 6. STATISTIKA
  1. Ukuran Pemusatan:
    Mean atau nilai rata-rata, adalah jumlah nilai dibagi banyak nilai. (Trik: pilih rata-rata sementara, gunakan selisih atau urutan)
    Median, nilai tengah, adalah nilai yang terletak ditengah-tengah data terurut. Untuk data interval, bahan-bahan yang digunakan adalah titik bawah kelas median, letak median, frekuensi median dan frekuensi kumulatif sebelum kelas median, dan interval kelas.
    Modus adalah nilai yang paling sering muncul. Untuk data interval, bahan-bahan yang digunakan adalah titik bawah kelas modus, frekuensi sebelum dan sesudah kelas modus, dan interval kelas.
  2. Kaidah Pencacahan, Permutasi, atau Kombinasi:
    Pencacahan, biasanya jika ditanyakan susunan angka.
    Ingat ada dua kata yang dipakai, SUSUN atau AMBIL.

    Kalau SUSUN semua, pasti faktorial.
    SUSUN tapi ada yang sama, faktorial dibagi faktorial yang sama.
    Nah, bila kata AMBIL, bila urutan diPERhatikan maka pasti menggunakan aturan PERmutasi, tapi bila urutan tidak diperhatikan (AB=BA) maka pasti menggunakan KOMBINASI.
    (Trik: PERMUTASI perkalian akhir. KOMBINASI perkalian akhir dibagi perkalian awal.)
  3. Peluang Kejadian:
    Teknik menentukan n(A) jumlah kejadian, dan n(S) jumlah keseluruhan ruang sampel adalah menggunakan kaidah pencacahan, permutasi atau kombinasi. Peluang kejadian adalah P(A) = n(A) / n(S)

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not permitting him to approach, and had brought him to the sight of the princess. But Bayard now, deceived like his master with the false intelligence of the goblin, submits to be mounted and to serve his master as usual, and Rinaldo, animated with rage, makes him fly toward Paris, more slowly than his wishes, though the speed of Bayard outstripped the winds. Full of impatience to encounter Orlando, he gave but a few hours that night to sleep. Early the next day he saw before him the great city, under the walls of which the Emperor Charles had collected the scattered remains of his army. Foreseeing that he would soon be attacked on all sides, the Emperor had caused the ancient
They descended from the mountain to the spot where the encounter had taken place. There they found the Hippogriff, with the magic buckler in its wrapper, hanging to his saddle-bow. Bradamante advanced to seize the bridle; the Hippogriff seemed to wait her approach, but before she reached him he spread his wings and flew away to a neighboring hill, and in the same manner, a second time, eluded her efforts. Rogero and the other liberated knights dispersed over the plain and hilltops to
object of my tenderest affection, my art having taught me that he is destined to become a Christian, and to perish, shortly after, by the blackest of treasons. "This youth, named Rogero, is the most beautiful and most accomplished of knights. It is I, the unhappy Atlantes, who have reared him from his
speedy return to France. BRADAMANTE AND ROGERO Bradamante, the knight of the white plume and shield, whose sudden appearance and encounter with Sacripant we have already told, was in
Brunello, interrupting, "that you shall not seek in vain; I have it all in writing, and I will myself conduct you." Bradamante, with thanks, accepted him for her guide. The host had a tolerable horse to dispose of, which Bradamante bargained for, and the next day, at the first dawn of morning, she took

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whose young trees were watered by two clear runnels, which came and mingled their waters, making a pleasing murmur. Believing herself far from Rinaldo, and overcome by fatigue and the summer heat, she saw with delight a bank covered with flowers so thick that they almost hid the green turf, inviting her to alight and rest. She dismounted from her
between the paynims, led by Rodomont, and the Christian forces. Rinaldo, witnessing from a mountain the prowess of Rodomont, left his troops in charge of his friends, and galloped towards him with his lance in rest. The impulse was irresistible, and Rodomont was unhorsed. But Rinaldo, unwilling to avail himself of his advantage, galloped back to the hill, and having secured Bayard among the baggage, returned to finish the combat on foot.
each knight resumed his own, and all, except the paladins and their friends, separated as their inclinations or duty prompted. Dudon, the Dane, one of the rescued knights, informed the cousins that he had been made prisoner by Morgana while in the discharge of an embassy to them from Charlemagne, who called upon them to return to the defence of
several encounters. Previously to this, however, Gano, or Ganelon (as he is sometimes called), the traitor, enemy of Orlando and the other nephews of Charlemagne, had entered into a traitorous correspondence with Marsilius, the Saracen king of Spain, whom he invited into France. Marsilius, thus encouraged, led an army across the frontiers, and joined Rodomont. This was the situation of things when Rinaldo and the other knights who had obeyed the summons of Dudon set forward on their
Having thus ended his tale, Rogero entreated a similar return of courtesy from his companion, who replied, without disguise, that she was of the race of Clermont, and sister to Rinaldo, whose fame was perhaps known to him. Rogero, much moved by this intelligence, entreated her to take off her helmet, and at the discovery of her face remained transported with delight. While absorbed in this contemplation, an unexpected danger assailed them. A party which was placed in a wood, in order to intercept the

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